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Mathematics 13 Online
OpenStudy (anonymous):

How do you calculate sin or cos using radicals and not using a calculator.

OpenStudy (anonymous):

What do you mean?

OpenStudy (anonymous):

sorry,sin 30 is .5...how do you get that?

OpenStudy (anonymous):

Do you know about special triangles? 45-45-90 and 30-60-90 triangles?

OpenStudy (anonymous):

ok, im working on coterminal angles....so tangent 390 coterminal angle is 30...then it asks for tan30 degree as a radical.

OpenStudy (anonymous):

@jevers01 you can calculate it easily through any metdology without remembering the formulas .first of all you need to do that.

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

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OpenStudy (anonymous):

thats the type of stuff im working on

OpenStudy (anonymous):

i just dont undertand how you can get an equation from sin, cos, or tangent.

OpenStudy (anonymous):

You have to form triangles...do you know how to do that within unit circles?

OpenStudy (anonymous):

NOPE

OpenStudy (anonymous):

Well, that's sort of an entire lesson to explain on here...I would suggest watching KhanAcademy videos on Trigonometry to help you through the basics

OpenStudy (anonymous):

here, try this ...sec of 390 is 2*sqrt3 / 3...how is that? where does those numbers come from?

OpenStudy (anonymous):

\[\frac{1}{\cos 390}\] The reference angle is 30 degrees so cos 30 degrees is \[\frac{\sqrt{3}}{2}\] So now you have \[\frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}}\] If you rationalize the denominator, you'll get 2*sqrt3 / 3

OpenStudy (anonymous):

I know cos 30 degrees is that from memory, but you can work out special triangles manually, it just takes longer

OpenStudy (anonymous):

ok i think i might finally get it...

OpenStudy (anonymous):

by george i think i got it lol...I was trying to solve for cotangent before solving for tangent...

OpenStudy (anonymous):

thank you very much

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