Question

For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions. Show your work.

Answer 1

in
x^2 + 3x + j=0

This is a quadratic, and you can find its roots (solutions for x that make it true) using the quadratic formula
12(−b±b2−4ac ...√) where we match up the a,b,c with ax2+bx+c
You get real solutions when the stuff inside the square root is 0 or positive. People call the expression b2−4ac the DISCRIMINATE . So find all values of j (c in the equation) that make the discriminate ≥0