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OpenStudy (anonymous):
Factor:
2a^2 + 30a + 100
13 years ago
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Parth (parthkohli):
A good start is to factor out the 2.
\( \color{Black}{\Rightarrow 2(a^2 + 15a + 50)}\)
13 years ago
Parth (parthkohli):
\( \color{Black}{\Rightarrow 2(a^2 + 10a + 5a + 50)}\)
Can you manage now? Yes?
13 years ago
OpenStudy (anonymous):
i got that part, what what's next?
13 years ago
OpenStudy (anonymous):
i think its 50
13 years ago
OpenStudy (jiteshmeghwal9):
First breackout 30a such that if we multiply them we get 100a^2 & if we add them we get 30a
13 years ago
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OpenStudy (anonymous):
2a^2 + 30a + 100
factor completely
2(a^2 + 15a + 50)
2(a + 10)(a + 5) works as 10a + 5a = 15a & 10*5 = 50
13 years ago
OpenStudy (anonymous):
Thank youuu!
13 years ago
OpenStudy (jiteshmeghwal9):
so,\[2a^2+20a+10a+100\]\[2a(a+10)+10(a+10)\]\[(2a+10)(a+10)\]
13 years ago
Parth (parthkohli):
Hmm.
13 years ago
OpenStudy (anonymous):
wait, which one is right?
13 years ago
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Parth (parthkohli):
@elitepenguin Please don't \(\textbf{answer}\) the questions.
13 years ago
OpenStudy (anonymous):
ok
13 years ago
OpenStudy (anonymous):
2a^2+30a+100
2(a^2+15a+50)
2(a^2+10a+5a+50)
2(a{a+10}+5{a+10})
2({a+10}{a+5})
13 years ago
OpenStudy (anonymous):
basically you have to break the middle term (i.e 15a)into two values in such a way that when u multiply them u get 50 and when you add or minus them you get plus 15
for this question we use 10 and 5
10*5=50
10+5=+15
13 years ago
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