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Mathematics 9 Online
OpenStudy (anonymous):

The figure below shows two similar right triangular prisms.

OpenStudy (anonymous):

OpenStudy (anonymous):

What is the volume of Prism B rounded to the nearest hundredth cubic unit? 354.38 140.0 236.25 157.5

OpenStudy (paxpolaris):

first find the missing side of Prism B: what is it?

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

7.5 ?

OpenStudy (paxpolaris):

yes.

OpenStudy (paxpolaris):

\[\large \frac5x=\frac69\]\[\large x={5\cdot \cancel93 \over \cancel6 2}=15/2=7.5 \]

OpenStudy (paxpolaris):

now calculate the the volume of Prism B

OpenStudy (anonymous):

where did 9 come from?

OpenStudy (paxpolaris):

in similar shapes corresponding sides make the same ratio. I used 6 from prism A ... and 9 from B as a pair of corresponding sides.

OpenStudy (paxpolaris):

Volume of prism = (Area of base) \(\times\) (Height of prism)

OpenStudy (paxpolaris):

so what's your answer? @redsox

OpenStudy (anonymous):

a ?

OpenStudy (paxpolaris):

\[\Huge \color{green} \checkmark\] \[\Large V=\left( \frac 12\times 9 \times 10.5 \right)\times 7.5\]

OpenStudy (anonymous):

thanks

OpenStudy (paxpolaris):

there is also another way to find the volume of Prism B: first find the volume of Prism A \(=(1/2\cdot6\cdot7)\times5\) and then multiply it by \((3/2)^3\)... because 3/2 is the ratio of the sides

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