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OpenStudy (anonymous):
PLEASE HELP ME
Where does the graph of y=2x^2 - 9x -5 cross the x-axis?
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OpenStudy (anonymous):
crosses the \(x\) axis where
\[2x^2-9x-5=0\] can you solve it?
OpenStudy (anonymous):
not too bad because this one factors as \((x-5)(2x+1)=0\)
OpenStudy (anonymous):
@satellite73 i need like two points
OpenStudy (anonymous):
yes you do
OpenStudy (anonymous):
solve \(x-5=0\) and solve \(2x+1=0\)
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OpenStudy (anonymous):
These are the answer choices
-1/2 ,0 and 5,0
1/2,0 and -5,0
-5/2,0 and 1,0
5/2,0 and -1,0
OpenStudy (anonymous):
Ohhhhh ok
OpenStudy (anonymous):
if it is on the \(x\) axis the second coordinate is surely 0
question is what is the first coordinate
i am sure you can solve \(x-5=0\) right?
OpenStudy (anonymous):
Ok so one of the xs is 5
OpenStudy (anonymous):
yes
\((5,0)\) is where it crosses \(x\) axis
also \((-\frac{1}{2},0)\)
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OpenStudy (anonymous):
i think it might have been confusing because they wanted a coordinate rather than just the \(x\) value
OpenStudy (anonymous):
Thank u so much @satellite73
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