by substitution -x/6 + y/2=1/2 x/3-y/6=-3/4
just get the value of x from one and put into another u will get y
I think it becomes simple if we multiply 12 with both the equations first and then evaluate x or y for substitution..
can u show me how waterineyes?
Ditto to what @waterineyes said. Multiply EACH term by 12.
Equations will become: -2x + 6y = 6 4x - 2y = -9 Now, evaluate x or y here..
how?
Multiply EACH term in the top row that @waterineyes gave you by 2. Then add like terms to eliminate the x. -4x + 12y = 12 4x - 2y = -9 __________________ 0x + 10y = 3 So y = 3/10...plug that into ONE of the equations in order to solve for x.
thanks @coreylvaughn
You should be able to take it from there...
@coreylvaughn we have to do it by substitution and not by elimination..
No problem. Thank @waterineyes
how to do it @waterineyes
Ewwww...my apologies. Well at least now you know what y SHOULD come out to be once you've performed all substitutions.
Pick one row. ONE row. And solve for ONE variable (i.e. get that variable ALONE)
Plug whatever expression you get for that variable, into the SAME variable in the OTHER row. (Note: row = equation)
Firstly divide by -2 in the first equation: we will get: x - 3y = -3 So, x = 3y - 3 Put it in second: 4(3y - 3) - 2y = -9 12y - 2y = -9 + 12 10y = 3 y = 3/10 Now for x: x = 3y - 3 x = (9/10) - 3 x = -21/10
Thanks @waterineyes now I can solve some of the equation here
Welcome dear...
@waterineyes have a question in x dear?
x=3y-3 right? and y= 3/10?
I got it now. Thanks dear
Yes..
got it dear... Thanks a lot!
Sorry I was busy in something else.. You got y = 3/10 and you have x = 3y -3 to find x just put the value of y here..
Welcome dear..
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