PLEASE HELP EASY QUESTION
Where does the graph of y=2x^2-5x+3 cross the x-axis?

Question

PLEASE HELP EASY QUESTION
Where does the graph of y=2x^2-5x+3 cross the x-axis?

klimenkov · Answer

Solve an equation
$$2x^2-5x+3=0$$
and you will get 2 points on the x-axis where the graph crosses it

zzr0ck3r · Answer

do you know the "AC method" ?

anonymous · Answer

No but I really need help

campbell_st · Answer

factorise the quadratic

(2x - 3)(x - 1) = 0

this should help you find the intercepts

anonymous · Answer

The answer choices are 
-1/2,0 and -3,0
1/2,0 and 3,0
3/2,0 and 1,0
-3/2,0 and -1,0

zzr0ck3r · Answer

A*C = 6
-2*-3 = 6 and adds to -5
2x^2-5x+3= 2x^2 - 3x - 2x + 3 = x(2x-3)-1(2x-3) = (2x-3)((x-1)
set equal to 0
(2x-3)(x-1)=0
2x-3=0 or x-1=0
2x=3 or x=1
x=2/3 or x = 1

zzr0ck3r · Answer

there are two other ways to do this, one being "complete the square" and another is with the equation (-b +- sqrt(b^2-4ac))/2a but the method I showed is the first way I learned and its easy if your not used to completing the square