find the equation of the line passing through (0,-1),(1,3). Enter the equation as y=mx+b.
f(x)=4x-1
Steps should be explained, not just answers given
are u sure? I put y=4x-1 into graph and it doesn't pass thru those points? because thats what i got too
@Kathi26
@Hero is that the answer? i got y=4x-1
Let me see
ok. after, can u help me with a few more? then thats it? since I see you're smart:)
You probably won't understand those steps
There's more than one way to do these
So it is not what the other person said, its y=2x-1?
Hang on a sec
but the slope is 4..
I know, I goofed up, that's why I said hang on a sec
(x,y) = (0,-1) y = mx + b -1 = m(0) +b -1 = b (x,y) = (1,3) y = mx + b 3 = m(1) - 1 3+1 = m 4 = m y = 4x - 1
So that's the steps and 4 is the slope
Ok can u hlp with a few more! thanks so muuhc: which of these points lie on the line that passes through (6,2) with slope m=2/3? Select all answers that are correct. A) 3,0 B) (-4,0) C) (3,-2) D) (-3,-4)
You have to use the point slope formula \((y - y_1) = m(x - x_1)\)
ok
for the first ordered pair, i got y-0=2/3(x-0)
The first ordered pair is not (0,0)
im not sure how to check if the ordered pairs work
and i meant x-3
Well, you're supposed to use the point-slope formula to get the form y = mx+b
But you don't really have to do it that way
You can just continue using y = mx + b and substituting values to find m and b
Can u do that? i tried and can't get it
Basically, they give you one of the points (6,2) so we know y = mx + b becomes: 2 = 2/3(6) + b
Now just solve for b
Ok so b is -2
Very good
Now you have y = 2/3(x) - 2
What you need to do now is substitute the other points and see if you get equal numbers on both sides of the equal sign
then plug in ordered pairs. let me do that and tell u what i gott
I got A and D
3,0 and -3,-4
Yup, you got it :D
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