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when i use elimination to solve a system of equations, what do i do if there is nothing to eliminate? ex. 5x+4y=-6 3x-3y=4
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you can always eliminate ex multiply the first line by 3 and the second by -5
oh ok, i didn't know that you could multiply by two different numbers
Alternative Hint: \(y = -\large\frac{6 + 5x}{4}\) \(y = -\large\frac{3x - 4}{3}\)
Solve each for y, then set y = y and cross multiply
So \(\frac{6 + 5x}{4} = \frac{4 - 3x}{3}\) 3(6 + 5x) = 4(4-3x) then continue solving for x
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