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Solve using the quadratic formula. x² + x = 12
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\[x=-b+/-\sqrt(b^2-4ac)/2a\]
plug in a=1, b=1, c=-12
\[x = {-b \pm \sqrt{b^2 - 4ac} \over 2a}\]
^how did you do that :O
thx
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In the equation editor i wrote: x = {-b pm sqrt{b^2 - 4ac} over 2a}
the out side most brackets are for the "over" so that they dont mess with the "x ="
:O Thank you! I'll remember that.
=P heres another trick... If you want to include symbols like \(\pi\) or \(\sqrt{112}\) within your text without starting a new line you can do so by replacing the [ ] with ( )
Thanks!
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