Question

what is the work done in moving a test charge Q through a distance of 1 cm along the equitorial axis of an electric dipole?

Answer 1

i think it should be 0. 'cause the field (and hence the force) are perpendicular to the the equator of the dipole. whereas the displacement is along the equator. so this makes our force and displacement perpendicular to each other. and thus, work done is 0.

Answer 2

Vaidehi09 gave the right answer in terms of field.

It is also zero because the equatorial plane is equipotential.