A fish swimming in a horizontal plane has velocity vector vi = (4.00iˆ + 1.00ˆj) m/s at a point in the in the ocean where the position relative to a certain rock is vector ri = (10.00 iˆ – 4.00 ˆj ) m. After the fish swims with constant acceleration for 20.0 s, its velocity is vector vf = (20.00iˆ – 5.00ˆj) m/s. (a) What are the components of the acceleration? (b) What is the direction of the acceleration with respect to unit vector ˆi ? (c) If the fish maintains constant acceleration, where is it at t = 25.0 s and in what direction is
it moving?

Question

A fish swimming in a horizontal plane has velocity vector vi = (4.00iˆ + 1.00ˆj) m/s at a point in the in the ocean where the position relative to a certain rock is vector ri = (10.00 iˆ – 4.00 ˆj ) m. After the fish swims with constant acceleration for 20.0 s, its velocity is vector vf = (20.00iˆ – 5.00ˆj) m/s. (a) What are the components of the acceleration? (b) What is the direction of the acceleration with respect to unit vector ˆi ? (c) If the fish maintains constant acceleration, where is it at t = 25.0 s and in what direction is
it moving?

australopithecus · Answer

a) I got (0.8,0.2) for the acceleration coordinates

b) I got 250, how do I find the direction

c) I got the ppoint (360, 83.5), how do I find the direction?

australopithecus · Answer

Basically my question is how do I find the direction do I just calculate it using the points?

arctan(56/250)

anonymous · Answer

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