Question

An artillery shell is fired with an initial velocity of 280 m/s at 65.0° above the horizontal. It explodes on a mountainside 36.0 s after firing. What are the x and y components of the shell where it explodes, relative to its firing point?

I got
V_ix = 280sin(65) = 118m/s
V_iy = 280cos(65) = 254m/s

I have tried to use the equations

vector r_fx = 118t + (1/2)(9.8)t^(2) at 36 seconds

vector r_fy = 254t + (1/2)(9.8)t^(2) at 36 seconds

and neither are giving me the right answer where am I going wrong?

Answer 1

I figured it out I just needed to use equations

xf = Vicos(theta)t
and
yf = Visin(theta) - 1/2(g)t^(2)

Answer 2

thanks

Answer 3

np :)