OwlKid's puzzle. A yard sale is selling Lay's packets each for $1. For every three waste wrappers you give him, you get another packet. How many Lay's packets can you buy if you have $15?
I didn't know you liked rap music Parth ;-) (typo?) 1 packet per $1 = rate 3 packet's wrappers = +1 more packet (for free, yes)? \[f(d) = \lfloor \frac{4}{3}\cdot (1 \frac{packet}{$})\cdot (d \ \ $) \rfloor\] I think? I've never been very strong with these types of problems
That's a floor function btw, truncates, since you can't have a third of a packet. Find f(15)
Also Parth, I thought you hated integrals?
Wow. I prefer it manually.
And yeah, for free.
twenty one?
Close, but not correct.
25
Hmm. Still close.
hmmm
22...
Right there. What water said.
$15=15p+15w 15w=5p+5w 3w=1p 1p+2w=1p $15=15p+5p+1p+1p=22p
\( \color{Black}{\Rightarrow $15 \Longrightarrow 15packs \Longrightarrow 15 wrappers \Longrightarrow +5packs \Longrightarrow 3 + 2 wrappers}\) \(\Longrightarrow +1pack + 2wrappers \Longrightarrow 1 wrapper + 2 wrappers \Longrightarrow 3 \)wrappers. 15 + 5 + 1 + 1 = 22
See, we bought 15 packets with $15 directly.. Now out of 15 packets we have 15 wrappers.. So, for every 3 wrapper we get 1 so 15 wrappers will give us 5 more packets.. Now, we have 5 wrappers, out of 5 wrappers, we will get 1 more packet.. Now, this 1 packet and that remaining two wrapper will make 3 wrappers that is 1 more packet.. So, 15 + 5 + 1 + 1 = 22
Great job, both of you!
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