If N = {positive integers} and subset C = {positive even integers}, what is C′? {1, 3, 5, 7, …} { } {… −7, −5, −3, −1} {2, 4, 6, 8, …}
{1,2,3,4....}-{2,4,6,....} =?
?
There a two families or set of integers or whole numbers. The first set, is the even numbers and the next is odd numbers {1, 3, 5, 7, 9,.......} See if you can continue this set?
Is it C.?
or A.?
{1,2,3,4....}-{2,4,6,....} =? So you knock out 2,4,6 etc from the first one, you are left with what?
1,3,5,7...
Is that right?
Don't you know?
Um no
Better, why don't you know?
I think its A. or C. but im not sure.
Hey, I'm.confused now too:) That is the positive odd numbers. Also, you have the positive even numbers too! Then, the negative odd and negative even numbers too.
Ok, we are starting out with N = {positive integers} That's what it says in the question. Agreed?
Yes
Well Sam the first example that I gave was the correct awnser.
OK, So that's {1,2,3,4...} Agreed?
We are trying to see how to get the answer, not just give the answer (ideally)
Yes
Then the question says that we have a subset (ie a part ) of the one we just looked at... Agreed?
Yep
That part is {2,4,6,....}Right?
mhmm
That a yes?
Yes
Right, the C' is basically saying what is left in the first set after you took away the second one....
That's the only tricky bit.....
ie N= C +C'
When all sets under consideration are considered to be subsets of a given set U, the absolute complement of A (denoted A') is the set of all elements in U but not in A.
Which is why my first reply was {1,2,3,4....}-{2,4,6,....} =?
Get it or not?
Yea i understand now thanks a lot
ur welcome
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