x+3/x-4 + x/4-x add and simplify if possible
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i dont understand what im supposed to do with these kind of problems and the way its set up
Hint: \(\large\frac{x+3}{x - 4} = -\frac{x+3}{4-x}\)
So: Replacing that, you get \(-\large\frac{x+3}{4-x} + \frac{x}{4-x} \) now just add
carefully
I'm basically showing you the stuff books won't show you
3 ----- 4 - x ?
Almost, you made a slight mistake. It's actually \(-\large\frac{3}{4-x} \)
its a multiple choice and thats not an option but 3 over (4 - x) is
What are the other options?
The answer is \(-\frac{3}{4-x}\) but even the book can make mistakes
(2x + 3) 2x+ 3 ------- and ------- x - 4 4- x
3 ---- 4 - x
those are the three options
lol, the book made a mistake
I don't know what to tell you
okay.. thanks
actually it is \(\frac{3}{x-4}\)
Somehow I goofed up on the negative
Oh, I see
What I posted was also correct
\(-\frac{3}{4-x} = \frac{3}{x-4}\)
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