Solve the following system of equations. Show Me How To Do This Please..! ^_^

4x + 3y = -1
3x + y = 3

Question

Solve the following system of equations. Show Me How To Do This Please..! ^_^

4x + 3y = -1
3x + y = 3

anonymous · Answer

What methods have you learned so far?

anonymous · Answer

The method of elimination and substitution.

anonymous · Answer

u can use them, elimination is awesome.

anonymous · Answer

Let's try substitution. From here I can tell that the easiest thing we can so is substitute the y from the second equation into the first one but we want to isolate y first.

anonymous · Answer

$$3x + y = 3 $$$$3x-3x + y = 3-3x $$$$ y = 3-3x $$

anonymous · Answer

Now we substitute the equation to the first one which is 
$$4x + 3y = -1$$

anonymous · Answer

okay yes...Then what..?

anonymous · Answer

That then becomes $$4x + 3(3-3x) = -1$$ the y disappears

anonymous · Answer

now solve that equation for x

anonymous · Answer

Can you tell me what you get?

anonymous · Answer

first lets eliminate x:

multiply both eqtns by a number that will make the value of their Xs equal:

(4x+3y= -1) 3
(3x + y= 3) 4

we will have new sets of eqtns:

12x+9y=-3
(-) 12x +4y=12

subtracting, wecan eliminate x and the answer will be:

5y= -15
therefore, y = -3

substituting the value of y to any of the eqtn, we can get:

3x + (-3) = 3
x = 1

to check, just substitute the values of x and y. :)

anonymous · Answer

okay thank you