Question

In the figure below two congruent squares touch at one corner. One side of the square measures 5 cm. The triangle created from two of the common sides is a right triangle. Find the area (to the nearest tenth) of the entire figure.

Answer 1

That implies that the triangle right there is half the area of the blue square;

Answer 2

And if we separate each square into two triangles, then you'll get 5 congruent triangles.

Answer 3

Each triangle has height 5, base 5\[\large \frac{bh}{2}=\frac{5*5}{2}\]

We have 5 triangles, therefore \(\huge \frac{5*5}{2}*5=\frac{5^3}{2}\)

Answer 4

o_o oh

Answer 5

was that all there was to it?

Answer 6

Yeah

Answer 7

thanks

Answer 8

yw Ledduh :)

Answer 9

-_-

Answer 10

:D