Question

How would solve 3n^4-4n^2+1=0 by factoring?

Answer 1

substitute t = n^2

Answer 2

My teacher wants us to use either factoring or the quadratic formula on these problems.

Answer 3

Yes. first you have to change it to quadratic then you can factor

Answer 4

okay let me see...

Answer 5

kayyy

Answer 6

use this hint
\[\large 3n^4-4n^2+1=3n^4-3n^2-(n^2-1)=3n^2(n-1)-(n-1)(n+1)\]

Answer 7

Yes grouping gives quick factors here. check the steps of @mukushla

Answer 8

thank y'all.