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solve 8^(y - 3) = 2^y
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polynomials again? :D
yes :P
would you like the real or alternative solution? :3
the answer haha i'm so lost...
\[8^{(y-3)}= 2^{y}\] the idea is to have the same base: \[2^{3(y-3)} =2^{y}\] 3(y-3) = y 3y-9 = y solve for y
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(8^y)(8^-3)=2^y 8^y * -24 =2^y -8^y =-8^y -24= -6^y -24/-6 4=y
thank you !!!!!!!!!!!!! :D
what I got was this from wolfram
np .
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8^y)(8^-3)=2^y
8^y * -24 =2^y
mulla you incorrect
I think the answer is |dw:1342635265134:dw|
ledah you are correct, mull and aly check my methodology above and follow it
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if 9/2 is 4.5 then i got it right :P
oohh am sorry..iits my bad! :(
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