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nd the zeros of the function f(x) = 2x3 – 9x + 3
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finding the zeros means solving the equation \[ \large f(x)=0 \]
So: \[2x^3-9x+3=0\] Do you know how to continue?
a little more please
I suggest the Newton Method to find the roots.
\[x_{n+1}=x_n - \frac{f(x)}{f'(x)} \]
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then use iteration until you find a result you are happy with.
@rdiddy212 do u know derivatives to do what @Spacelimbus suggested?
Refer to attached plot. The roots, calculated by the Mathematica function, NSolve, are the following to 15+ digits:\[\{-2.2716332985527448,0.34224143691160663,1.9293918616411379\} \]
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