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how do i solve 12x^2=36. Give both exact solutions and approximate solution to the nearest hundredth.
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You don't need quadratic formula here, 12x^2=36 x^2=3 \[x= \pm \sqrt{3}\]
so basically how do i do this? do i just simplify?
\[ 12x^2=36\] divide both sides by 12 \[ x^2=3\] square root both sides x=±√3
so what if its (x+3)^2=81
then square root both sides first (x+3)^2=81 \[x+3=\pm \sqrt{81}\]
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oh okay so its ±√81?
\[x+3=\pm \sqrt{81}\] \[x+3=\pm 9\] ------------------------------------ x+3=9 and x+3=-9 x=6 x=-12
If there is square of x at L.H.S then after taking it to other side it will be sqrt of 36 so ,\[12x=\sqrt{36}\]\[12x=6\]\[x=\frac{6}{12} \implies \frac{1}{2}\]
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