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(√6)^8x = 216^x -3
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\[(\sqrt 6)^{8x} = 216^{x-3}\] \[(6^{1/2})^{8x} = (6^3)^{x-3}\] \[6^{8x/2} = 6^{3(x-3)}\] \[6^{4x} = 6^{3x - 9}\] 4x = 3x - 9 solve for x now
x = -9. But when you made the bases the same, I completely don't understand that..
\[\sqrt{6} = 6^{1/2}\] do you agree?
yes.
\[216 = 6^3\] agree?
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ohh I see what you did there now. The ^1/2 threw me off in the beginning
Thanks :)
haha you're welcome :)
wait uhh i still don't get it. how does 6=6 1/2?
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