A rhombus has a short diagonal of 24 cm and a long diagonal of 32 cm. What is the perimeter of the rhombus?
I ended up getting 60 as my best guess.
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You gotta find the hypotenuse of the right triangle that you see right there. Then, you multiply that by 4(because all the sides are equal). Crappy diagram - but you get the point.
If they had a rotate button for the square tool :P
I might post that in feedback... anyways
Nope. A rhombus \(\ne\) square, fyi.
Yeah I know but still a rotating button could be useful for diamonds :P
Back to the question. You find the hypotenuse by Pythagorean Theorem. \( \color{Black}{\Rightarrow 24^2 + 32^2 = \text{Side of the rhombus}^2}\)
A diamond \(\ne\) square, either ;)
You D:< idea ruin-er xD
lol :)
I would divide both diagonals by 2 before using pythagoras
Thanks for reminding that. Whoops.
\( \color{Black}{\Rightarrow 12^2 + 16^2 = \text{side of a rhombus}^2}\)
was I supposed to do 12*12?
or 12*2 and 16*2 =80
the little 2 in the upper right means multiply by itself twice. so \( 12^2\) = 12*12 so the side of the rhombus squared =12*12+16*16 remember to take the square root to find the side then multiply by 4 to get the perimeter.
ah
okay
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