The equation of a line is y=-1/2x-1. what is the equation of the line that is perpendicular to the first line and passes through the point (2,-5)?

Question

anonymous · Answer

You will have follow this steps:
To find the slope of the perpendicular:
Slope=opposite inverse of the perpendicular's slope.

Then you will use this:
y−y1=m(x−x1)

Where m is the slope and 
(x1, y1) is the point

Please, tell us what are you getting.

anonymous · Answer

I still dont get it. Can you help me some more? please

anonymous · Answer

We have that the slope of the original line is: -1/2
Which is the opposite inverse of -1/2?

anonymous · Answer

@NaeNae16 Are you still with us? :)

anonymous · Answer

but im still not sure what to do

anonymous · Answer

The opposite inverse of -1/2=2
So the slope of the line that we are looking for is m=2
Now you have to use this equation:
y-y1=m*(x-x1)
and using this: (x1,y1)=(2,-5)
Come on, give it a try!

anonymous · Answer

yes I get it Thanks :)