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Lines CD and DE are tangent to circle A shown below. If CE is 112°, what is the measure of ∡CDE? 124° 136° 68° 56°
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@Calcmathlete .. So is it the same thing here or something different ?
\[\angle CDE = \frac{1}{2}(arc CBE - arc{CE})\]
how do we find what CBE equals?
\[CBE = 360-CE\]
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is the answer 136 ?
No
Did you multiply by 1/2?
Divide 136 by 2 and you have your answer :)
68?
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