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Mathematics 12 Online
OpenStudy (anonymous):

x''=k/x^2 Find x'

OpenStudy (anonymous):

integrate x'=-k/x+C

OpenStudy (anonymous):

if i did not get this let me know

OpenStudy (anonymous):

Surely it's a differential equation?

OpenStudy (anonymous):

it is not since you need just x' if you need x then it is

OpenStudy (anonymous):

What are integrating with respect to, then?

OpenStudy (anonymous):

I have x''x'dt=x'dt k/x^2 x' d(x')=k/x^2 dx Integrating: 0.5 (x')^2=-k/x

OpenStudy (anonymous):

if this is differential equation then it is non linear and these equation needs higher level maths to be solved.

OpenStudy (anonymous):

I ask in the context of gravitation (x=displacement), and my answer makes no sense in that way, so it's most probably wrong.

OpenStudy (experimentx):

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