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What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form?
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do you know the relationship between gradients of two perpendicular lines?
no
well, they have an inverse negative relationship, i.e if gradient of line 1 is m the gradient of the line perpendicular to it is \[-1/m\]
what is the answer
don't you want to know how to do it?
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yes i'm saying.. the process
in your case the gradient is 1/3 so (y-1) / (x--6) = 1/3 3(y-1) = x+6 3y-3 = x+6 3y = x+6-3 y = 1/3x +3
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