A fish swimming in a horizontal plane has velocity vector vi = (4.00iˆ + 1.00ˆj) m/s at a point in the in the ocean where the position relative to a certain rock is vector ri = (10.00 iˆ – 4.00 ˆj ) m. After the fish swims with constant acceleration for 20.0 s, its velocity is vector vf = (20.00iˆ – 5.00ˆj) m/s.

(c) If the fish maintains constant acceleration, where is it at t = 25.0 s and in what direction is it moving?

How do I find the direction it is moving I have that

a =(0.8, -0.3)
rf = (360, -72.8)

Question

A fish swimming in a horizontal plane has velocity vector vi = (4.00iˆ + 1.00ˆj) m/s at a point in the in the ocean where the position relative to a certain rock is vector ri = (10.00 iˆ – 4.00 ˆj ) m. After the fish swims with constant acceleration for 20.0 s, its velocity is vector vf = (20.00iˆ – 5.00ˆj) m/s.

(c) If the fish maintains constant acceleration, where is it at t = 25.0 s and in what direction is it moving?

How do I find the direction it is moving I have that

a =(0.8, -0.3)
rf = (360, -72.8)

anonymous · Answer

direction of the fish is the direction of the instantaneous velocity vector

australopithecus · Answer

how do I find that?