Mathematics
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OpenStudy (anonymous):
What is the solution to the equation log(2) x + log(2) 4 = 3 ?
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Parth (parthkohli):
A good start is knowing what \(\log _24 \) equals.
OpenStudy (anonymous):
I know i have to re-write the equation but i don't know what to change it to to make it... addable.
Parth (parthkohli):
Never worry about that. Can you tell me what \(\log_2 4\) is equal to?
Parth (parthkohli):
You don't need a calculator to calculate \(\log_24\). What power of 2 is 4?
OpenStudy (anonymous):
2
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Parth (parthkohli):
There you go. So \(\log_24 = 2\).
Now we have something like \(\log_2x + 2 = 3\).
Parth (parthkohli):
Subtract 3 from both sides to start with.
Parth (parthkohli):
\(\log_2x = 3 - 2\).
My mistake - subtract 2 from both sides.
OpenStudy (anonymous):
so log(2) x=1
which means x is .10? or is that wrong?
Parth (parthkohli):
\(\log_2x = 1\)
This just means that 2 to some power is 1.
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Parth (parthkohli):
What power of \(2\) is \(1\)?
OpenStudy (anonymous):
Blah .5.
OpenStudy (anonymous):
so x is equal to .5
Parth (parthkohli):
How is \(2^{0.5} = 1?\)
OpenStudy (lgbasallote):
careful
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OpenStudy (lgbasallote):
\[\Large \log_2 x = 1 \implies 2^1 = x\]
Parth (parthkohli):
Hmm.
Parth (parthkohli):
What lgbasallote said.
Parth (parthkohli):
What is \(2^1\)?
OpenStudy (lgbasallote):
oh man..long have i waited to say that \m/
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Parth (parthkohli):
I see.
OpenStudy (anonymous):
isn't 2^1=2?
Parth (parthkohli):
Yep
Parth (parthkohli):
So that's it. \(x = 2\).
OpenStudy (anonymous):
But then dosn't log(2)2+log(2)4 not equal 3? it would equal 4.
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Parth (parthkohli):
How so?
Parth (parthkohli):
\( \color{Black}{\Rightarrow \log_22 = 1, \log 2_4 = 2 \Longrightarrow 2 + 1 = 3}\)
OpenStudy (anonymous):
oh i see now! I'm a moron sorry! thank you for your help :)
Parth (parthkohli):
Heh. You're welcome!