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OpenStudy (anonymous):

The first (ΔiH1) and the second (ΔiH) ionization enthalpies (in kJ mol–1) and the (ΔegH) electron gain enthalpy (in kJ mol–1) of a few elements are given below: Elements ΔiH ΔiH ΔegH I 520 7300 –60 II 419 3051 –48 III 1681 3374 –328 IV 1008 1846 –295 V 2372 5251 +48 VI 738 1451 –40 Which of the above elements is likely to be : (a) the least reactive element. (b) the most reactive metal. (c) the most reactive non-metal. (d) the least reactive non-metal.

OpenStudy (anonymous):

@apoorvk Plzz Help!!

OpenStudy (anonymous):

Least reactive non metal as it varies with the Characteristics of it

OpenStudy (anonymous):

SO....

OpenStudy (anonymous):

wat will be the answer lol

OpenStudy (anonymous):

Plz with expl ...

OpenStudy (anonymous):

How elements are classified in the periodic table? http://answers.yahoo.com/question/index?qid=20090911022355AA4WTfq

OpenStudy (anonymous):

hey u see plzz read my question lol

OpenStudy (anonymous):

First my friend u look to it atleast

OpenStudy (anonymous):

it is abt ionization energy and electron gain enthalpy

OpenStudy (anonymous):

nsdl.niscair.res.in/bitstream/.../revised+periodic+properties.pdf

OpenStudy (cwrw238):

sorry - long times since i did this stuff

OpenStudy (anonymous):

@apoorvk help plzzz

OpenStudy (apoorvk):

Oh man - just 108 repetitions wouldn't please me I am no God. -.- lol

OpenStudy (anonymous):

u r not comminh thats why i am sorry!!!

OpenStudy (apoorvk):

Lol haha.. anyways.. the most reactive element would require the least energy to get ionised. Use this funda.

OpenStudy (apoorvk):

In fact, we had done a similar question here yesterday - why don't you go through it, and reply what you think about this one.

OpenStudy (anonymous):

but electron gain enthalpy also given

OpenStudy (anonymous):

i tried to answer this my own but that was wrong

OpenStudy (anonymous):

@apoorvk r u there

OpenStudy (anonymous):

@apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk @apoorvk

OpenStudy (anonymous):

Help plzzz

OpenStudy (anonymous):

u kno wat ionisation enthalpy is ?

OpenStudy (anonymous):

yup the min amt of energy req to remove an electron

OpenStudy (anonymous):

well that's ionisation energy..... :P anyways nd wer do u have a prob solving this problem then?

OpenStudy (anonymous):

i need to find those elements

OpenStudy (anonymous):

ya ikr.......well wat did u understand after reading the question wat are ur inferences?

OpenStudy (anonymous):

i only knw that electron gain enthalpy of noble gas are positve so element 5 is noble gas

OpenStudy (anonymous):

and ionization ener of reactive metals will be low

OpenStudy (anonymous):

so which one is it 1 or 2

OpenStudy (anonymous):

which one do you think it is?

OpenStudy (anonymous):

i think 1

OpenStudy (anonymous):

nd y do u think it's 1?

OpenStudy (anonymous):

becoz it has first ioni low and second high .........

OpenStudy (anonymous):

so? u got a periodic table? i suggest u check those values for intial elements of 1a nd elements of 2a............

OpenStudy (anonymous):

should be consider low negative electron gain enthalpy for reactive metal

OpenStudy (anonymous):

no lol

OpenStudy (anonymous):

not by peri o table

OpenStudy (anonymous):

check it somehow.................i really dont care how u get those values

OpenStudy (anonymous):

Plzzz help

OpenStudy (anonymous):

@apoorvk knw s to do by with out looking pt

OpenStudy (anonymous):

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OpenStudy (anonymous):

can u solve plzzzz

OpenStudy (anonymous):

@ujjwal plzzz help

OpenStudy (anonymous):

@heena @radar help

OpenStudy (anonymous):

@timo86m

OpenStudy (anonymous):

Let me give you a hint for each question a) You've already answered this one the least reactive element is the one that takes the most energy to remove an electron from the atom. and even more for the second one. Also this element would require energy in order to increase its electron density. b) This is sort of an opposite question to a) (understand that it doesn't matter if its a non metal or not, generally metallic elements are often more reactive than non metals) its now asking which element has the (fill in the gap) first and second ionization enthalpy. Also its true that for this element to gain another electron would be very easy. There is only on sensible choice that satisfies both conditions. c) So this is the biggest hint, usually non-metals have first ionization enthalpies of >1000kj/mol but look at elements III and IV (electron gain enthalpy specifically) does something strike you? That should give you a hint what kind of elements they are. d) If you answered a,b and c this should be the easiest question out of all of them.

OpenStudy (anonymous):

did nt understand @apoorvk help

OpenStudy (apoorvk):

Please read what Wulusi has written above, I don't think I can explain any better than him

OpenStudy (anonymous):

i cant understand him

OpenStudy (anonymous):

plzzz tell me one by one

OpenStudy (apoorvk):

@wulusi - please post it 'one-by-one' :P

OpenStudy (anonymous):

he is offline lol

OpenStudy (anonymous):

@Omniscience

OpenStudy (mathteacher1729):

@Yahoo! I am a bit rusty on my chemistry and would have to go and consult a text or online resource before I could give a meaningful answer here. Sorry.

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