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Double check my work?? (3d)^3(d) = 3d^4 (3d^2)^2 = 3d^4
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\[(3d)^{3d} = 3^{3d} d ^{3d} = (3^{3})^{d} (d ^{3})^{d} = (27d ^{3})^{d}\] this is how it should be.
oh wait, is that question \[(3d)^{3}d\] ?
no it's (3d^2) ^ 2
no D after the parenthesis
no, i'm referring to the first equation u've posted.
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Oh yeah sorry, you got it right the second time!
oh...then the answer to the first one will be (3^3)(d^4) and that to the second one will be (3^2)(d^4). the power will be distributed to both 3 and d, not only to d.
Okay, thank you! (:
sure, np! i hope u understood what i did?
yes! It helped, thank you again (:
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glad to be of help!
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