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Mathematics 26 Online
OpenStudy (anonymous):

Double check my work?? (3d)^3(d) = 3d^4 (3d^2)^2 = 3d^4

OpenStudy (anonymous):

\[(3d)^{3d} = 3^{3d} d ^{3d} = (3^{3})^{d} (d ^{3})^{d} = (27d ^{3})^{d}\] this is how it should be.

OpenStudy (anonymous):

oh wait, is that question \[(3d)^{3}d\] ?

OpenStudy (anonymous):

no it's (3d^2) ^ 2

OpenStudy (anonymous):

no D after the parenthesis

OpenStudy (anonymous):

no, i'm referring to the first equation u've posted.

OpenStudy (anonymous):

Oh yeah sorry, you got it right the second time!

OpenStudy (anonymous):

oh...then the answer to the first one will be (3^3)(d^4) and that to the second one will be (3^2)(d^4). the power will be distributed to both 3 and d, not only to d.

OpenStudy (anonymous):

Okay, thank you! (:

OpenStudy (anonymous):

sure, np! i hope u understood what i did?

OpenStudy (anonymous):

yes! It helped, thank you again (:

OpenStudy (anonymous):

glad to be of help!

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