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MIT 18.01 Single Variable Calculus (OCW)
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INTEGRATION: How would you integrate sqrt(4 - x^2) on [-2, 2]? appreciate the help
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|dw:1342951626845:dw| let y = sqrt (4- x^2), we can see y^2+x^2=4,that is a disk ,when x in between -2 to 2, across to the definetion of integrate ,the integrate we want,is just the area up x axis ,which is a half disk, so ,the answer is 2pi
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