Question

12) How many numbers greater than 100 and less than 10 000 may be formed using the digits 2, 3, 4 and 5 if each digit may be used more than once?

Answer 1

ummm Infinite
I m not sure

Answer 2

See, the number greater than 100 and less than 1000 will have how many digits in each number??

Answer 3

need at least 3 digits.

Answer 4

use permutations

Answer 5

Not Atleast

Exactly 3..

Because if it has 4 then the number will become 1000..

And we have to ding the numbers between 100 and 1000 but not including 100 and 1000..

Getting??

Answer 6

find in place of ding sorry..

Answer 7

the numbers can contain either 3 or 4 digits right?

Answer 8

but four digits can be 2345, 2354, 3245, etc.

Answer 9

still above 100 and under 1000.

Answer 10

not under 1000, its 10000

Answer 11

Oh sorry I interpreted the question wrong.

Answer 12

10000*

Answer 13

Yes..

It can be of 3 and it can be of 4..

Answer 14

So firstly we find for 3 digits number that is : 101 to 999

Now tell me about the hundredths place??

101 has 1 as its hundredth place..

it can be 2, 3. 4, 5 , 6 , 7 , 8, 9..
But we have to find the numbers containing 2, 3, 4 and 5

So hundredth place can take 2, 3, 4 and 5...

4 ways..
Getting??

Answer 15

so,
in case 1: count the number of 3 digit numbers.

each place can take up 4 digits.
so, number of possibilities is 4*4*4.
in case 2: count the number of 4 digit numbers.

each place can take up 4 digits.
so, number of possibilities is 4*4*4*4.