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OpenStudy (anonymous):
x/3 = 2x + 1
-1 = 2x - x/3
-3 = 6x - x
-3 = 5x
then x = -3/5 = -0.6
OpenStudy (anonymous):
Thank you
OpenStudy (anonymous):
What is x^???
OpenStudy (anonymous):
X (squared) to waterineyes
OpenStudy (anonymous):
Then the answer is wrong.
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OpenStudy (anonymous):
It will become a quadratic equation and x will have two solutions and not one..
OpenStudy (anonymous):
is it (1/3)*x6 or 1/3x^2
OpenStudy (anonymous):
1/3x^2 sai1234
OpenStudy (anonymous):
\[\frac 13x^2 = 2x + 1\]\[\frac 13 x^2 - 2x - 1 = 0\]At this point, I tend to multiply by 3 to get rid of the fraction.\[3(\frac 13x^2 - 2x - 1 = 0)\]\[x^2 - 6x - 3 = 0\]Can you solve from here?
OpenStudy (anonymous):
Multiply by 3 both the sides:
\[x^2 = 6x + 3 \implies x^2 - 6x - 3 = 0\]
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OpenStudy (anonymous):
You have to use here quadratic formula:
\(D = b^2 - 4ac\)
\[x = \frac{-b \pm \sqrt{D}}{2a}\]
here a = 1 , b = -6 and c = -3
plug in the values and then find x..
OpenStudy (anonymous):
so where does D come in?
OpenStudy (anonymous):
ahh i see
OpenStudy (anonymous):
D is Discriminant..
OpenStudy (anonymous):
D=b2−4ac
x2−6x−3=0 compare with ax^2+bx+c=0
to get a,b,c values
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