Question

1/3 x^=2x+1 solve by an appropriate technique??

Answer 1

x/3 = 2x + 1
-1 = 2x - x/3
-3 = 6x - x
-3 = 5x
then x = -3/5 = -0.6

Answer 2

Thank you

Answer 3

What is x^???

Answer 4

X (squared) to waterineyes

Answer 5

Then the answer is wrong.

Answer 6

It will become a quadratic equation and x will have two solutions and not one..

Answer 7

is it (1/3)*x6 or 1/3x^2

Answer 8

1/3x^2 sai1234

Answer 9

\[\frac 13x^2 = 2x + 1\]\[\frac 13 x^2 - 2x - 1 = 0\]At this point, I tend to multiply by 3 to get rid of the fraction.\[3(\frac 13x^2 - 2x - 1 = 0)\]\[x^2 - 6x - 3 = 0\]Can you solve from here?

Answer 10

Multiply by 3 both the sides:

\[x^2 = 6x + 3 \implies x^2 - 6x - 3 = 0\]

Answer 11

You have to use here quadratic formula:

\(D = b^2 - 4ac\)

\[x = \frac{-b \pm \sqrt{D}}{2a}\]

here a = 1 , b = -6 and c = -3

plug in the values and then find x..

Answer 12

so where does D come in?

Answer 13

ahh i see

Answer 14

D is Discriminant..

Answer 15

D=b2−4ac
x2−6x−3=0 compare with ax^2+bx+c=0
to get a,b,c values

Answer 16

-6+-square root 48/2 is what i have?