The local zoo has two water tanks for the elephant exhibit that are leaking One water tank contains 12 gal of water and is leaking at a constant rate of 3 gal/h. The second water tank contains 8 gal of water and is leaking at a constant rate of 5 gal/h. When will the two tanks have the same amount of water? Explain. Let x = the number of hours the tanks are filling and let y = the number of gallons in the tank.

Question

anonymous · Answer

A(h)=(rate)(number of hours)+Starting amount of water

$$r_1=-3$$
$$r_2=-5$$

$$y_1=12$$
$$y_2=8$$

$$A(t)=-3h+12$$
$$B(t)=-5h+8$$

anonymous · Answer

to find out when they equal the same amount, create an equality

-3h+12=-5h+8

$$2h=-4$$

$$h=-2$$


these two water holding devices will never have the same amount

anonymous · Answer

thanks man appericate it needed that one