Question

can someone help me with this question attachment's in comment

Answer 1

\[8\sqrt{2x-4}=32\]

Answer 2

Can you frame the equation needed to solve this ?
Area of a rectangle = length \(\times\) width

Answer 3

yes my equation is the same as @nitz's

Answer 4

but i don't know how to solve for x when it's in a radical

Answer 5

Now square both sides. See if it helps removing the radical sign (after first dividing both sides by 8)

Answer 6

\[\sqrt{2x-4}=4\]

Answer 7

just solve for x budi nitz got it right

Answer 8

okay i got 4=\[\sqrt{2x-4}\]

Answer 9

now square both sides......

Answer 10

?????

Answer 11

2x-4=16
2x=20
x=10