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Mathematics 8 Online
OpenStudy (anonymous):

simplify (x^2+2x/12x+54)-(3-x/8x+36)

OpenStudy (anonymous):

do you know how to subtract fractions?

OpenStudy (anonymous):

idk .

OpenStudy (anonymous):

all i know what t do is with the denoms

OpenStudy (anonymous):

to *

OpenStudy (anonymous):

you're right, that gives you the least common multiplier, and in your case it is: (12x+54)(8x+36)

OpenStudy (anonymous):

okay , well what do i do with that ?

OpenStudy (anonymous):

now divide this with numerator of first fraction, what do you get?

OpenStudy (anonymous):

im sorry but im not following with what ur telling me to do . could u show me what u mean? i am genuinely really confused about this .

OpenStudy (anonymous):

(x^2+2x/12x+54)-(3-x/8x+36) =(x^2+2x/12x+54) *(12x+54)(8x+36) - (3-x/8x+36)(12x+54)(8x+36) do you follow

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

yea , that makes sense , go ahead .

OpenStudy (anonymous):

simplify further: (x^2+2x)(8x+36) - (3-x)( (12x+54) now can you open the parenthesis?

OpenStudy (anonymous):

like foil ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

sure , h/o

OpenStudy (anonymous):

when i foiled i got 8x^3+30x^2+54x+162 , thats without grouping and finding the gcf .

OpenStudy (anonymous):

???

OpenStudy (anonymous):

close but not yet there try it this way: \[x ^{2}(8x+36)+2x(8x+36) - (3(12x+54)-x(12x+54))\]

OpenStudy (anonymous):

doesnt it come out to be the same thing ?

OpenStudy (anonymous):

lets find out: \[8x ^{3} +36x ^{2} +16x ^{2} +72x- (36x+162-12x ^{2}-54x)\]

OpenStudy (anonymous):

like terms together: \[8x ^{3} +64x ^{2}+90x-162\] should be the correct answer

OpenStudy (anonymous):

okay , then what happens ? like r the denoms gone now ?

OpenStudy (anonymous):

yes, they disappeared when we multiplied by the LCM , the last expression is the answer

OpenStudy (anonymous):

okayy then . sorry about me not being able to help much , this stuff just confuses me alot !

OpenStudy (anonymous):

practice makes perfect

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