A square pyramid has a slant height of 5 feet and a height of 4 feet. What is the surface area if the square base has sides of length 6 feet? Can you explain it? Thanks!
Find the area of the base first: \[Base(Area) = Side^2\] Side is given as 6.. Can you find the base area.???
So it would be Base(A) = 6^2 making 36?
Yes you are right..
What next?
Now Surface Area of Square Pyramid is given by: \[\large \color{green}{SA = Base \;Area + 2 \times s \times l}\]
Here you have found the base area.. s is side given that is 6.. l is the slant height that is 5.. Can you plug in the values to solve..
Alright gimie a sec.
Remember one thing: We are given with Height too that is 4 feet but to find the surface area we need to haver height.. Yeah that height is surely used in finding the volume of Square Pyramid..
Take your time..
SA= 96?
Absolutely.. Well done..
Don't forget to use the units that for Area are \(feet^2\)..
Thank you!
Did you understand the whole thing??
I want you too remember the formula for Surface Area so that next time you can do it yourself only..
*to in place of too
Good Luck.. Welcome dear..
Yeah you find the BA the plug the values in and it was 96FT^2
Yes... Absolutely.. You are a good learner too..
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