A square pyramid has a slant height of 5 feet and a height of 4 feet. What is the surface area if the square base has sides of length 6 feet? Can you explain it? Thanks!

Question

A square pyramid has a slant height of 5 feet and a height of 4 feet. What is the surface area if the square base has sides of length 6 feet?  Can you explain it? Thanks!

anonymous · Answer

Find the area of the base first:

$$Base(Area) = Side^2$$

Side is given as 6..

Can you find the base area.???

anonymous · Answer

So it would be Base(A) = 6^2 making 36?

anonymous · Answer

Yes you are right..

anonymous · Answer

What next?

anonymous · Answer

Now Surface Area of Square Pyramid is given by:

$$\large \color{green}{SA = Base \;Area + 2 \times s \times l}$$

anonymous · Answer

Here you have found the base area..

s is side given that is 6..

l is the slant height that is 5..

Can you plug in the values to solve..

anonymous · Answer

Alright gimie a sec.

anonymous · Answer

Remember one thing:

We are given with Height too that is 4 feet but to find the surface area we need to haver height..

Yeah that height is surely used in finding the volume of Square Pyramid..

anonymous · Answer

Take your time..

anonymous · Answer

SA= 96?

anonymous · Answer

Absolutely..

Well done..

anonymous · Answer

Don't forget to use the units that for Area are $feet^2$..

anonymous · Answer

Thank you!

anonymous · Answer

Did you understand the whole thing??

anonymous · Answer

I want you too remember the formula for Surface Area so that next time you can do it yourself only..

anonymous · Answer

*to in place of too

anonymous · Answer

Good Luck..

Welcome dear..

anonymous · Answer

Yeah you find the BA the plug the values in and it was 96FT^2

anonymous · Answer

Yes...
Absolutely..

You are a good learner too..