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(3ab)(-5ab)?
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Multiple the like-terms in each brackets: That is: 3 x - 5 = -15 a x a = a^2 b x b = b^2 ANS:\[-15a^2b^2\]
When you times, you add the exponents. each a and b has an exponent of 1 so (3ab)(-5ab) = \( (3a^1b^1)(-5a^1b^1) \) \( (3a^1b^1)(-5a^1b^1) \) 3 times -5 = -15 \( a^1 \times a^1 = a^{1 +1} = a^{2}\) \( b^1 \times b^1 = b^{1 +1} = b^{2}\) Put it all together and we have\( -15a^2b^2 \) like compassionate stated.
Allow me to return the favor.
:-D ty
is −15a2b2
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