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Mathematics 22 Online
OpenStudy (anonymous):

(3ab)(-5ab)?

OpenStudy (compassionate):

Multiple the like-terms in each brackets: That is: 3 x - 5 = -15 a x a = a^2 b x b = b^2 ANS:\[-15a^2b^2\]

OpenStudy (anonymous):

When you times, you add the exponents. each a and b has an exponent of 1 so (3ab)(-5ab) = \( (3a^1b^1)(-5a^1b^1) \) \( (3a^1b^1)(-5a^1b^1) \) 3 times -5 = -15 \( a^1 \times a^1 = a^{1 +1} = a^{2}\) \( b^1 \times b^1 = b^{1 +1} = b^{2}\) Put it all together and we have\( -15a^2b^2 \) like compassionate stated.

OpenStudy (compassionate):

Allow me to return the favor.

OpenStudy (anonymous):

:-D ty

OpenStudy (anonymous):

is −15a2b2

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