Question

a state's high school athletic association separates its schools into two divisions. together div I and II have a total of 300 schools. there are about 6 times as a many schools in div I than div II. how many schools are in eatch div?

just devided by 300/6 for div II. and 300-div II for div I?? or is there any formula???

Answer 1

Hint: Use a system of equations.

Answer 2

Do you know what that is?

Answer 3

a = div I b= div II
6a+b=300????

Answer 4

No, you're method is good, but let Div: 1 = x, and Div: 2 = y

That is,

x + y = 300

Answer 5

6 times as a many schools in div I than div II tho..???

Answer 6

...you need to define your variables !

let x = # of schools in division I

let y = # of schools in division II

then,

x + y = 300
x = 6y

Answer 7

The first part says Div: 1, and Div: 2 = 300

that is,

x + y = 300

The second part says, "there are about 6 times as a many schools in div I than div II."

Thus,

x = 6y

Answer 8

However, it says, "About 6 times."

x + y = 300
x ≈ 6y

Answer 9

^ Can you take it from here?

Answer 10

thanks ;]

Answer 11

No problem.