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Graph the equation y = x2 - 3x -4. For what value or values of x is y = 0
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This is asking for the solutions to the quadratic because the solutions are where y = 0. Set y = 0. \[0 = x^2 - 3x - 4\]Can you factor this?
x2 messing me up is it just x+x-3x-4
No. \[x^2 = x \times x\]
What 2 factors of -4 add up to -3?
-4+1
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Alright. Place the factors into their positions. \[x^2 - 3x - 4 = 0\implies (x - 4)(x + 1) = 0\]Now, remember how 0 times anything equals 0?
4
Alright. That's one value. x = 4. Now do the same for the other part. x + 1 = 0 x = ?
sorry this is times so I'm super stressed
No problem. x = 4, -1 For those values, y is equal to 0.
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thank you so much for walking me through it
np :)
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