can someone please answer this question for me? The ratio of the present ages of two museums is 3 to 5. Twelve years ago, the sum of their ages was less than 56 years. Find the possibilities for the present age of the younger museum.
I found this on http://en.allexperts.com/q/Advanced-Math-1363/2008/11/help-15.htm I hope it helps. 12 years ago is spoke of, so we can drop b) and c). If d) were true, 12 years ago museum A would barely have been made (age 0). There is only one choice left. a.) Between 18 years and 32 years b.) Between 10 years and 24 years c.) Between 8 years and 18 years d.) Between 12 years and 30 years
you could have the present age of the younger museum be x. thus the present age of the older museum will be 5/3 x (due to the ratio given). 12 years ago, the younger museum's age: x-12 and older museum: 5/3x-12 adding the two should give 56. (x-12)+(5/3x-12)=56 work out for x
thank you so much you guys! i am not good with ratios at all.
you're welcome :)
:)
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