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I have a trig identities question that i need some explaining on please
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sin 120 \[= \sqrt{3} \over 2\]
yes
i dont understand how to have squareroot answers
like how do i solve this w.o a calculator
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you want the value of \[\sqrt{3}\]
???
no, how do i know what sin 120 equals without the use of a calculator ?
do you know sine and cosine values for 0,30,45,60,90. 'coz these are important
and sin(pi-x)=sinx
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so \[\sin (\pi -x) = sinx\]
?
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