The digits 5, 3, 6, 2 and 7 are used to make a 5-digit number. How many different numbers are possible if the digits 3, 2 and 7 must be together?
36 is the answer
You may choose 3 digits out of 5, and you may place them in different orders. Right?
So, it is \(_5P^3\)
Do you know how to calculate permutations?
5P3=60 and that's not the answer.
Is 36 the answer, plz tel me
36 is indeed correct, stated by @nishika17
Oh! It's something else. Never mind.
I read the question differently—my apologies.
I also calculated it correctly but want to know why the 5-digit part has no affect?
3! x 3!=36
Right there.
The number of ways three digits can stay together is 3!.
is it 5! * 3! = 720 ??
ok, I understand @ParthKohli, thanks.
You're welcome!
@ganpat that is not correct.
oh sorry, i meant 3! * 3! = 36.. :(
hey, can you help me out with this @ParthKohli Maria, Steven, James, Sofia, Nin and Alfredo are standing next to each other. Calculate how many ways this can be done if Maria and James are not to stand next to each other.
Hint: Probability of them not standing next to each other = 1 - P(Standing each other).
yep but I don't know how to find the standing next to each other part.
There are 5 ways for them to stand with each other. M J _ _ _ _ _ M J _ _ _ _ _ M J _ _ _ _ _ M J _ _ _ _ _ M J
Well, the number of ways they don't stand together is the number of ways all could stand - the number of ways they stand together.
is there another way to figure it out besides listing it?
the 5 ways for them to stand with each other*
I find the 'listing' way visual—and that is how I learnt it.
okok.
The number of ways the 6 people may stand = 6! = 720 Now subtract 5 from 720, and you get 715.
Is that the right answer?
Wait.. I am confused whether to divide of subtract.
nope it's 6!-2!x5!=480
or*
Oh. I am confused myself now :/
Let me just review the concept. Sorry for the inconvenience.
it's ok.
Well. 5 ways to place them, but when we do, we have 4 blanks left. The ways you could fill those 4 spots is 4! = 24. Then, we multiply the number of ways to place M and J, and get 24 * 5 = 120.
Hmm... you should look at the 3rd here - http://answers.yahoo.com/question/index?qid=20100206071826AAPHkCK
I am confused on the second question that you asked :/
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