Mathematics
63 Online
OpenStudy (anonymous):
Lol I might jsut be stupid but idk how to do this xD
Find the value of the cot 10° using your calculator.
IDK HOW D; It's my last question I don't have a cot button on my calc either if I'm supposed to and and
12 years ago
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OpenStudy (anonymous):
do tan 10 then put 1 ÷ Ans
12 years ago
OpenStudy (anonymous):
Firstly find tan10..
12 years ago
OpenStudy (anonymous):
cot=1/tg
12 years ago
OpenStudy (anonymous):
Or you could do 1 ÷ (tan 10)
12 years ago
OpenStudy (anonymous):
oh. I am stupid. My bad. Thanks guys :D
12 years ago
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OpenStudy (anonymous):
Welcome dear..
12 years ago
OpenStudy (anonymous):
\[\cot \theta = \frac{1}{\tan \theta} = \frac{\cos \theta}{\sin \theta}\]
12 years ago
OpenStudy (anonymous):
np :)
12 years ago
OpenStudy (anonymous):
^_^
12 years ago
OpenStudy (anonymous):
going hard @agentx5
12 years ago
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OpenStudy (anonymous):
:O AGENT D: -___-
12 years ago
OpenStudy (anonymous):
I can make it more hard:
\[\cot \theta = \frac{1}{\tan \theta} = \frac{\sin(2 \theta)}{2\sin^2 \theta}\]
12 years ago
OpenStudy (anonymous):
oh wait xD Is that tan^-1 or tan (10)
12 years ago
OpenStudy (anonymous):
lol "more hard"
12 years ago
OpenStudy (anonymous):
tan10..
12 years ago
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OpenStudy (anonymous):
YES @waterineyes
12 years ago
OpenStudy (anonymous):
Double angles rule!
12 years ago
OpenStudy (anonymous):
0.176?
12 years ago
OpenStudy (anonymous):
@rebeccaskell94 i think now you are getting more confused..
12 years ago
OpenStudy (anonymous):
no no no not the same thing dear Rebecca! :-D
\[\tan^{-1} (\frac{opp}{adj}) = \arctan (\frac{opp}{adj}) = \theta\]
12 years ago
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OpenStudy (anonymous):
lol Agent your genius talents are commendable
12 years ago
OpenStudy (anonymous):
Now use:
1/0.176
12 years ago
OpenStudy (anonymous):
Inverse tangent is cotangent, anti-tangent is arctangent. The latter returns and angle value in degrees or radians :-)
12 years ago
OpenStudy (anonymous):
@rebeccaskell94 You forgot to do the rciprocal. Now. 1/0.176326981...
12 years ago
OpenStudy (anonymous):
5.671? o.o
12 years ago
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OpenStudy (anonymous):
THat's what I get :)
12 years ago
OpenStudy (anonymous):
oh dang.
12 years ago
OpenStudy (anonymous):
May be..
Ha ha ha..
12 years ago
OpenStudy (anonymous):
3:)
12 years ago
OpenStudy (anonymous):
Can anyone find this without calculator??
12 years ago
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OpenStudy (anonymous):
o_O No idea...
12 years ago
OpenStudy (anonymous):
Is Wolfram considered a calculator? XD
12 years ago
OpenStudy (anonymous):
Can anybody think about finding the above value without using calculator??
Question changed to this one now..
12 years ago
OpenStudy (anonymous):
I can... I think...
|dw:1343070912188:dw|
12 years ago