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OpenStudy (anonymous):
What are the x-intercept(s) of the graph of y + 6 = x2 − x?
OpenStudy (anonymous):
there.isn't.any
OpenStudy (anonymous):
there isnt
,
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
how do yo get people to answer questions.. lol
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OpenStudy (anonymous):
lol..idk
OpenStudy (anonymous):
4
6x – 5
x + 2
3x – 5
OpenStudy (anonymous):
factor the gcf
OpenStudy (anonymous):
which.is.2?
OpenStudy (anonymous):
2(6x^2-17+12)
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OpenStudy (anonymous):
ok take common 2 from the given you get
2(6x^-17x+10)
now break the midterm
2(6x^2-12x-5x+10)
are you following?
OpenStudy (anonymous):
@TiaW
OpenStudy (anonymous):
@huneya.
where.the.12.comefrom?
OpenStudy (anonymous):
yes.i.think.so
OpenStudy (anonymous):
do.u.break.it.down.again?
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OpenStudy (anonymous):
ok (-12x-5x)=-17x
i hope it is clear
so now factor as
2((6x(x-2)-5(x-2))
are you getting this ??
OpenStudy (anonymous):
no...what.happen.to.the.17
OpenStudy (anonymous):
i just broke it as we can write -17x x as
-12x-5x
correct??
OpenStudy (anonymous):
@TiaW
OpenStudy (anonymous):
ok...i.think.i.got.it
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OpenStudy (anonymous):
ok did you get this step?
so now factor as
2((6x(x-2)-5(x-2))
OpenStudy (anonymous):
not.at.all
OpenStudy (anonymous):
@sami-21 i got 2(2x-3)(3x-4)
OpenStudy (anonymous):
ok
2(6x^2-12x-5x+10)
taking 6x common from the first two terms from 6x^2-12x we can write as
6x(x-2)
now taking -5 common from the last two terms from -5x+10 we can write it as
-5(x-2)
so combing the above two
2((6x(x-2)-5(x-2))
is it ok now ?
OpenStudy (anonymous):
@TiaW ,@huneya got it ?
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OpenStudy (anonymous):
ok...i.got.it
OpenStudy (anonymous):
6x-5?
OpenStudy (anonymous):
is it okay now ?? can you do the rest by yourself just take x-2 common and there you are.
OpenStudy (anonymous):
@huneya is it ok?
OpenStudy (anonymous):
yeah.its.ok..thnxx
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