what is the solution of (143(5)+67)5 Summer school algebra sucks
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jimthompson5910 (jim_thompson5910):
Follow the order of operations
jimthompson5910 (jim_thompson5910):
You might have been taught PEMDAS
jimthompson5910 (jim_thompson5910):
The P stands for "P"arenthesis. So you do everything in the parenthesis first.
jimthompson5910 (jim_thompson5910):
So just focus on 143(5)+67
Then we move to the E, which is "E"xponents. I don't see any exponents here, so let's move on
Then the M, which is "M"ultiplication. So what is 143 times 5?
OpenStudy (anonymous):
143 times 5 is 715
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jimthompson5910 (jim_thompson5910):
good so
(143(5)+67)5
becomes
(715+67)5
jimthompson5910 (jim_thompson5910):
Now we reset and go back to P in PEMDAS. We still have parenthesis, so we stick to the stuff inside the parenthesis
jimthompson5910 (jim_thompson5910):
Then onto E. Still no exponents, so we move on...
jimthompson5910 (jim_thompson5910):
Then to M. We're not multiplying inside the parenthesis, so we move on
jimthompson5910 (jim_thompson5910):
Then D. Are we dividing inside the parenthesis?
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OpenStudy (anonymous):
i don't think so
jimthompson5910 (jim_thompson5910):
no, we're just adding
jimthompson5910 (jim_thompson5910):
715 plus 67 is 782
So
(715+67)5
then turns into
(782)5
jimthompson5910 (jim_thompson5910):
and this is the same as saying
782 times 5
OpenStudy (anonymous):
so it equals 3,910?
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