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Mathematics 16 Online
OpenStudy (anonymous):

what is the solution of (143(5)+67)5 Summer school algebra sucks

jimthompson5910 (jim_thompson5910):

Follow the order of operations

jimthompson5910 (jim_thompson5910):

You might have been taught PEMDAS

jimthompson5910 (jim_thompson5910):

The P stands for "P"arenthesis. So you do everything in the parenthesis first.

jimthompson5910 (jim_thompson5910):

So just focus on 143(5)+67 Then we move to the E, which is "E"xponents. I don't see any exponents here, so let's move on Then the M, which is "M"ultiplication. So what is 143 times 5?

OpenStudy (anonymous):

143 times 5 is 715

jimthompson5910 (jim_thompson5910):

good so (143(5)+67)5 becomes (715+67)5

jimthompson5910 (jim_thompson5910):

Now we reset and go back to P in PEMDAS. We still have parenthesis, so we stick to the stuff inside the parenthesis

jimthompson5910 (jim_thompson5910):

Then onto E. Still no exponents, so we move on...

jimthompson5910 (jim_thompson5910):

Then to M. We're not multiplying inside the parenthesis, so we move on

jimthompson5910 (jim_thompson5910):

Then D. Are we dividing inside the parenthesis?

OpenStudy (anonymous):

i don't think so

jimthompson5910 (jim_thompson5910):

no, we're just adding

jimthompson5910 (jim_thompson5910):

715 plus 67 is 782 So (715+67)5 then turns into (782)5

jimthompson5910 (jim_thompson5910):

and this is the same as saying 782 times 5

OpenStudy (anonymous):

so it equals 3,910?

jimthompson5910 (jim_thompson5910):

you are correct

jimthompson5910 (jim_thompson5910):

So in the end, (143(5)+67)5 = 3910

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