Question

Help

Answer 1

Using the formula \[n/6(n+1)(2n+1) \]
evaluate \[\sum_{i=4}^{2}2i^2\]

Answer 2

that should be a 7 on top on the sigma, NOT a 2

Answer 3

does this formula even work for starting values of i>1

Answer 4

the formula u gave is for calculating the sum of the squares of the first n natural numbers. i doubt we can use it in this case since we're not using the first n natural numbers here....we're starting from 4. is it given that we have to use that formula?