Question

c+(4-3c)-2=0 help me solve this plez

Answer 1

get rid of the parenthesis
\[c + 4 - 3c - 2 = 0\]
combine like terms
\[4 - 2c - 2 = 0\]
add 2c to both sides
[4 - 2 = 2c\]
simplify

Answer 2

\[4 - 2 = 2c\]
simplify

Answer 3

huh

Answer 4

can u call me so u can expain it to me i still dont get it

Answer 5

which part dont you get?

Answer 6

adding 2c to both sides

Answer 7

\[\large{c+4-3c-2=0}\]
\[\large{c-3c+4-2=0}\]
\[\large{c(1-3)+2=0}\]
\[\large{c(-2)+2=0}\]
\[\large{-2c+2=0}\]
Did u get what i did yet?

Answer 8

You Have to isolate the c

Answer 9

@ME39 ... do reply ..

Answer 10

\[4 - 2c + 2 = 0\]
add 2c to both sides
\[4 - 2c + 2 + 2c = 0 + 2c\]
\[4 + 2 + 0 = 2c\]
\[4 + 2 = 2c\]
do you see it now?

Answer 11

do i isolate the c start n from the beginning of the problem

Answer 12

no you need to expand first

Answer 13

by that i mean combining like terms

Answer 14

\[\large{-2c+2=0}\]
\[\large{-2c+2-2=0-2}\]
\[\large{-2c=-2}\]
\[\large{\frac{-2c}{-2}=\frac{-2}{-2}}\]
\[\large{\frac{\cancel{-2}^{1}c}{\cancel{-2}^1}=\frac{\cancel{-2}^1}{\cancel{-2}^1}}\]
\[\large{c=1}\]

Answer 15

8508680042 is there anyway u can call me plz

Answer 16

@lgbasallote u understood the quest. wrong i think

Answer 17

yes i did

Answer 18

yeah i mistyped sorry

Answer 19

what i wrote first was right though lol

Answer 20

No problem ..

@ME39 Where r u having problems dude ..

If you need an online tutor : you can instead go to khan academy videos